3-5i/-2i

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Solution for 3-5i/-2i equation:


i in (-oo:+oo)

3-(((5*i)/(-2))*i) = 0

(5/2)*i^2+3 = 0

5/2*i^2 = -3 // : 5/2

i^2 = -6/5

i belongs to the empty set

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