3-6(5y+4)=3(-y+1)-6

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Solution for 3-6(5y+4)=3(-y+1)-6 equation: 



3-6(5y+4)=3(-y+1)-6

We move all terms to the left:

3-6(5y+4)-(3(-y+1)-6)=0

We add all the numbers together, and all the variables

-6(5y+4)-(3(-1y+1)-6)+3=0

We multiply parentheses

-30y-(3(-1y+1)-6)-24+3=0



We calculate terms in parentheses: -(3(-1y+1)-6), so:

3(-1y+1)-6

We multiply parentheses

-3y+3-6

We add all the numbers together, and all the variables

-3y-3

Back to the equation:

-(-3y-3)



We add all the numbers together, and all the variables

-30y-(-3y-3)-21=0

We get rid of parentheses

-30y+3y+3-21=0

We add all the numbers together, and all the variables

-27y-18=0

We move all terms containing y to the left, all other terms to the right

-27y=18

y=18/-27

y=-2/3

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