3-6(x+5)=17(1-x)

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Solution for 3-6(x+5)=17(1-x) equation: 



3-6(x+5)=17(1-x)

We move all terms to the left:

3-6(x+5)-(17(1-x))=0

We add all the numbers together, and all the variables

-6(x+5)-(17(-1x+1))+3=0

We multiply parentheses

-6x-(17(-1x+1))-30+3=0



We calculate terms in parentheses: -(17(-1x+1)), so:

17(-1x+1)

We multiply parentheses

-17x+17

Back to the equation:

-(-17x+17)



We add all the numbers together, and all the variables

-6x-(-17x+17)-27=0

We get rid of parentheses

-6x+17x-17-27=0

We add all the numbers together, and all the variables

11x-44=0

We move all terms containing x to the left, all other terms to the right

11x=44

x=44/11

x=4

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