3-7(1-2b)=-6b+4(2+8b)

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Solution for 3-7(1-2b)=-6b+4(2+8b) equation: 



3-7(1-2b)=-6b+4(2+8b)

We move all terms to the left:

3-7(1-2b)-(-6b+4(2+8b))=0

We add all the numbers together, and all the variables

-7(-2b+1)-(-6b+4(8b+2))+3=0

We multiply parentheses

14b-(-6b+4(8b+2))-7+3=0



We calculate terms in parentheses: -(-6b+4(8b+2)), so:

-6b+4(8b+2)

We multiply parentheses

-6b+32b+8

We add all the numbers together, and all the variables

26b+8

Back to the equation:

-(26b+8)



We add all the numbers together, and all the variables

14b-(26b+8)-4=0

We get rid of parentheses

14b-26b-8-4=0

We add all the numbers together, and all the variables

-12b-12=0

We move all terms containing b to the left, all other terms to the right

-12b=12

b=12/-12

b=-1

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