3-7(2a+3)=3(-4a-5)+(-2a)-3

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Solution for 3-7(2a+3)=3(-4a-5)+(-2a)-3 equation: 



3-7(2a+3)=3(-4a-5)+(-2a)-3

We move all terms to the left:

3-7(2a+3)-(3(-4a-5)+(-2a)-3)=0

We multiply parentheses

-14a-(3(-4a-5)+(-2a)-3)-21+3=0



We calculate terms in parentheses: -(3(-4a-5)+(-2a)-3), so:

3(-4a-5)+(-2a)-3

We multiply parentheses

-12a+(-2a)-15-3

We get rid of parentheses

-12a-2a-15-3

We add all the numbers together, and all the variables

-14a-18

Back to the equation:

-(-14a-18)



We add all the numbers together, and all the variables

-14a-(-14a-18)-18=0

We get rid of parentheses

-14a+14a+18-18=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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