3-7/2y+16/3y-5=y-2y+2

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Solution for 3-7/2y+16/3y-5=y-2y+2 equation:



3-7/2y+16/3y-5=y-2y+2
We move all terms to the left:
3-7/2y+16/3y-5-(y-2y+2)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
We add all the numbers together, and all the variables
-7/2y+16/3y-(-1y+2)+3-5=0
We add all the numbers together, and all the variables
-7/2y+16/3y-(-1y+2)-2=0
We get rid of parentheses
-7/2y+16/3y+1y-2-2=0
We calculate fractions
1y+(-21y)/6y^2+32y/6y^2-2-2=0
We add all the numbers together, and all the variables
y+(-21y)/6y^2+32y/6y^2-4=0
We multiply all the terms by the denominator
y*6y^2+(-21y)+32y-4*6y^2=0
We add all the numbers together, and all the variables
32y+y*6y^2+(-21y)-4*6y^2=0
Wy multiply elements
6y^3-24y^2+32y+(-21y)=0
We get rid of parentheses
6y^3-24y^2+32y-21y=0
We do not support eypression: y^3

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