3-7y-3(2-3y)=4(y-1)

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Solution for 3-7y-3(2-3y)=4(y-1) equation: 



3-7y-3(2-3y)=4(y-1)

We move all terms to the left:

3-7y-3(2-3y)-(4(y-1))=0

We add all the numbers together, and all the variables

-7y-3(-3y+2)-(4(y-1))+3=0

We multiply parentheses

-7y+9y-(4(y-1))-6+3=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We add all the numbers together, and all the variables

2y-(4y-4)-3=0

We get rid of parentheses

2y-4y+4-3=0

We add all the numbers together, and all the variables

-2y+1=0

We move all terms containing y to the left, all other terms to the right

-2y=-1

y=-1/-2

y=1/2

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