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3-7y-3(2-3y)=4(y-1)-(y+1)
We move all terms to the left:
3-7y-3(2-3y)-(4(y-1)-(y+1))=0
We add all the numbers together, and all the variables
-7y-3(-3y+2)-(4(y-1)-(y+1))+3=0
We multiply parentheses
-7y+9y-(4(y-1)-(y+1))-6+3=0
We calculate terms in parentheses: -(4(y-1)-(y+1)), so:We add all the numbers together, and all the variables
4(y-1)-(y+1)
We multiply parentheses
4y-(y+1)-4
We get rid of parentheses
4y-y-1-4
We add all the numbers together, and all the variables
3y-5
Back to the equation:
-(3y-5)
2y-(3y-5)-3=0
We get rid of parentheses
2y-3y+5-3=0
We add all the numbers together, and all the variables
-1y+2=0
We move all terms containing y to the left, all other terms to the right
-y=-2
y=-2/-1
y=+2
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