3-7y-3(2-3y)=4(y-1)-(y+1)

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Solution for 3-7y-3(2-3y)=4(y-1)-(y+1) equation: 



3-7y-3(2-3y)=4(y-1)-(y+1)

We move all terms to the left:

3-7y-3(2-3y)-(4(y-1)-(y+1))=0

We add all the numbers together, and all the variables

-7y-3(-3y+2)-(4(y-1)-(y+1))+3=0

We multiply parentheses

-7y+9y-(4(y-1)-(y+1))-6+3=0



We calculate terms in parentheses: -(4(y-1)-(y+1)), so:

4(y-1)-(y+1)

We multiply parentheses

4y-(y+1)-4

We get rid of parentheses

4y-y-1-4

We add all the numbers together, and all the variables

3y-5

Back to the equation:

-(3y-5)



We add all the numbers together, and all the variables

2y-(3y-5)-3=0

We get rid of parentheses

2y-3y+5-3=0

We add all the numbers together, and all the variables

-1y+2=0

We move all terms containing y to the left, all other terms to the right

-y=-2

y=-2/-1

y=+2

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