3-8(2x-5)=9x-5(x+4)x=-4

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Solution for 3-8(2x-5)=9x-5(x+4)x=-4 equation: 



3-8(2x-5)=9x-5(x+4)x=-4

We move all terms to the left:

3-8(2x-5)-(9x-5(x+4)x)=0

We multiply parentheses

-16x-(9x-5(x+4)x)+40+3=0



We calculate terms in parentheses: -(9x-5(x+4)x), so:

9x-5(x+4)x

We multiply parentheses

-5x^2+9x-20x

We add all the numbers together, and all the variables

-5x^2-11x

Back to the equation:

-(-5x^2-11x)



We add all the numbers together, and all the variables

-(-5x^2-11x)-16x+43=0

We get rid of parentheses

5x^2+11x-16x+43=0

We add all the numbers together, and all the variables

5x^2-5x+43=0

a = 5; b = -5; c = +43;
Δ = b2-4ac
Δ = -52-4·5·43
Δ = -835
Delta is less than zero, so there is no solution for the equation

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