3-9(7m+12)=2(m-3)

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Solution for 3-9(7m+12)=2(m-3) equation: 



3-9(7m+12)=2(m-3)

We move all terms to the left:

3-9(7m+12)-(2(m-3))=0

We multiply parentheses

-63m-(2(m-3))-108+3=0



We calculate terms in parentheses: -(2(m-3)), so:

2(m-3)

We multiply parentheses

2m-6

Back to the equation:

-(2m-6)



We add all the numbers together, and all the variables

-63m-(2m-6)-105=0

We get rid of parentheses

-63m-2m+6-105=0

We add all the numbers together, and all the variables

-65m-99=0

We move all terms containing m to the left, all other terms to the right

-65m=99

m=99/-65

m=-1+34/65

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