3-I2m+7I=2

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Solution for 3-I2m+7I=2 equation: 



3-2I+7=2

We move all terms to the left:

3-2I+7-(2)=0

We add all the numbers together, and all the variables

-2I+8=0

We move all terms containing I to the left, all other terms to the right

-2I=-8

I=-8/-2

I=+4

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