3-c/c+1/6c+7/c+1-4

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Solution for 3-c/c+1/6c+7/c+1-4 equation: 


D( c )

c = 0

c = 0

c = 0

c in (-oo:0) U (0:+oo)

(1/6)*c+7/c-(c/c)-4+1+3 = 0

(1/6)*c+7/c-4-1+1+3 = 0

1/6*c^1+7*c^-1-1*c^0 = 0

(1/6*c^2-1*c^1+7*c^0)/(c^1) = 0 // * c^2

c^1*(1/6*c^2-1*c^1+7*c^0) = 0

c^1

(1/6)*c^2-c+7 = 0

(1/6)*c^2-c+7 = 0

DELTA = (-1)^2-(4*7*(1/6))

DELTA = -11/3

DELTA < 0

c in { } 

c belongs to the empty set

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