3-j+(-2+3j)(-0.707-0.707j)=0

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Solution for 3-j+(-2+3j)(-0.707-0.707j)=0 equation:



3-j+(-2+3j)(-0.707-0.707j)=0
We add all the numbers together, and all the variables
-j+(3j-2)(-0.707j-0.707)+3=0
We add all the numbers together, and all the variables
-1j+(3j-2)(-0.707j-0.707)+3=0
We multiply parentheses ..
(+0j^2-2.121j+0j+1.414)-1j+3=0
We get rid of parentheses
0j^2-2.121j+0j-1j+1.414+3=0
We add all the numbers together, and all the variables
j^2-2.121j+4.414=0
a = 1; b = -2.121; c = +4.414;
Δ = b2-4ac
Δ = -2.1212-4·1·4.414
Δ = -13.157359
Delta is less than zero, so there is no solution for the equation

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