3-k-(4)/5-(2k+1)=(1/1)

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Solution for 3-k-(4)/5-(2k+1)=(1/1) equation: 



3-k-(4)/5-(2k+1)=(1/1)

We move all terms to the left:

3-k-(4)/5-(2k+1)-((1/1))=0

We add all the numbers together, and all the variables

-k-(2k+1)+3-4/5-(0)=0

We add all the numbers together, and all the variables

-1k-(2k+1)+3-4/5=0

We get rid of parentheses

-1k-2k-1+3-4/5=0

We multiply all the terms by the denominator


-1k*5-2k*5-4-1*5+3*5=0

We add all the numbers together, and all the variables

-1k*5-2k*5+6=0

Wy multiply elements

-5k-10k+6=0

We add all the numbers together, and all the variables

-15k+6=0

We move all terms containing k to the left, all other terms to the right

-15k=-6

k=-6/-15

k=2/5

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