3-m(4m+1)=5m-25

Solution for 3-m(4m+1)=5m-25 equation:

3-m(4m+1)=5m-25

We move all terms to the left:

3-m(4m+1)-(5m-25)=0

We multiply parentheses

-4m^2-m-(5m-25)+3=0

We get rid of parentheses

-4m^2-m-5m+25+3=0

We add all the numbers together, and all the variables

-4m^2-6m+28=0

a = -4; b = -6; c = +28;
Δ = b2-4ac
Δ = -62-4·(-4)·28
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-22}{2*-4}=\frac{-16}{-8}
=+2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+22}{2*-4}=\frac{28}{-8}
=-3+1/2
$