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3-x+2=2(x-5)
We move all terms to the left:
3-x+2-(2(x-5))=0
We add all the numbers together, and all the variables
-1x-(2(x-5))+5=0
We calculate terms in parentheses: -(2(x-5)), so:We get rid of parentheses
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
-1x-2x+10+5=0
We add all the numbers together, and all the variables
-3x+15=0
We move all terms containing x to the left, all other terms to the right
-3x=-15
x=-15/-3
x=+5
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