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3-x/(x-3)(x+1)=2/x+1
We move all terms to the left:
3-x/(x-3)(x+1)-(2/x+1)=0
Domain of the equation: (x-3)(x+1)!=0
We move all terms containing x to the left, all other terms to the right
x-3)(x!=-1
x∈R
Domain of the equation: x+1)!=0We get rid of parentheses
x∈R
-x/(x-3)(x+1)-2/x-1+3=0
We multiply parentheses ..
-x/(+x^2+x-3x-3)-2/x-1+3=0
We calculate fractions
We do not support expression: x^3
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