3-x=4(-3-2x)+8

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Solution for 3-x=4(-3-2x)+8 equation: 



3-x=4(-3-2x)+8

We move all terms to the left:

3-x-(4(-3-2x)+8)=0

We add all the numbers together, and all the variables

-x-(4(-2x-3)+8)+3=0

We add all the numbers together, and all the variables

-1x-(4(-2x-3)+8)+3=0



We calculate terms in parentheses: -(4(-2x-3)+8), so:

4(-2x-3)+8

We multiply parentheses

-8x-12+8

We add all the numbers together, and all the variables

-8x-4

Back to the equation:

-(-8x-4)



We get rid of parentheses

-1x+8x+4+3=0

We add all the numbers together, and all the variables

7x+7=0

We move all terms containing x to the left, all other terms to the right

7x=-7

x=-7/7

x=-1

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