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3-y(7+2y)=4y
We move all terms to the left:
3-y(7+2y)-(4y)=0
We add all the numbers together, and all the variables
-y(2y+7)-4y+3=0
We add all the numbers together, and all the variables
-4y-y(2y+7)+3=0
We multiply parentheses
-2y^2-4y-7y+3=0
We add all the numbers together, and all the variables
-2y^2-11y+3=0
a = -2; b = -11; c = +3;
Δ = b2-4ac
Δ = -112-4·(-2)·3
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{145}}{2*-2}=\frac{11-\sqrt{145}}{-4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{145}}{2*-2}=\frac{11+\sqrt{145}}{-4} $
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