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3-y=2/y
We move all terms to the left:
3-y-(2/y)=0
Domain of the equation: y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
-y-(+2/y)+3=0
We add all the numbers together, and all the variables
-1y-(+2/y)+3=0
We get rid of parentheses
-1y-2/y+3=0
We multiply all the terms by the denominator
-1y*y+3*y-2=0
We add all the numbers together, and all the variables
3y-1y*y-2=0
Wy multiply elements
-1y^2+3y-2=0
a = -1; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·(-1)·(-2)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-1}{2*-1}=\frac{-4}{-2} =+2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+1}{2*-1}=\frac{-2}{-2} =1 $
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