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3-z+3/10=3z-4/5+2z-15
We move all terms to the left:
3-z+3/10-(3z-4/5+2z-15)=0
Domain of the equation: 5+2z-15)!=0We add all the numbers together, and all the variables
We move all terms containing z to the left, all other terms to the right
2z-15)!=-5
z∈R
-z-(5z-4/5-15)+3+3/10=0
We add all the numbers together, and all the variables
-1z-(5z-4/5-15)+3+3/10=0
We get rid of parentheses
-1z-5z+15+3+4/5+3/10=0
We calculate fractions
There is no solution for this equation
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