3.5(+2x+2)=2(4.5x+1)x

Solution for 3.5(+2x+2)=2(4.5x+1)x equation:

3.5(+2x+2)=2(4.5x+1)x

We move all terms to the left:

3.5(+2x+2)-(2(4.5x+1)x)=0

We add all the numbers together, and all the variables

3.5(2x+2)-(2(4.5x+1)x)=0

We multiply parentheses

7x-(2(4.5x+1)x)+7=0


We calculate terms in parentheses: -(2(4.5x+1)x), so:

2(4.5x+1)x

We multiply parentheses

8x^2+2x

Back to the equation:

-(8x^2+2x)


We get rid of parentheses

-8x^2+7x-2x+7=0

We add all the numbers together, and all the variables

-8x^2+5x+7=0

a = -8; b = 5; c = +7;
Δ = b2-4ac
Δ = 52-4·(-8)·7
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{249}}{2*-8}=\frac{-5-\sqrt{249}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{249}}{2*-8}=\frac{-5+\sqrt{249}}{-16}
$