3/(2/2y)=3

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Solution for 3/(2/2y)=3 equation: 


D( y )

(2/2)*y = 0

(2/2)*y = 0

(2/2)*y = 0

y = 0

y in (-oo:0) U (0:+oo)

3/((2/2)*y) = 3 // - 3

3/((2/2)*y)-3 = 0

3*y^-1 = 3 // : 3

y^-1 = 1

-1 < 0

1/(y^1) = 1 // * y^1

1 = 1*y^1 // : 1

1 = y^1

y = 1

y = 1

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