3/(2b-1)=2/(b+2)

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Solution for 3/(2b-1)=2/(b+2) equation: 


D( b )

2*b-1 = 0

b+2 = 0

2*b-1 = 0

2*b-1 = 0

2*b-1 = 0 // + 1

2*b = 1 // : 2

b = 1/2

b+2 = 0

b+2 = 0

b+2 = 0 // - 2

b = -2

b in (-oo:-2) U (-2:1/2) U (1/2:+oo)

3/(2*b-1) = 2/(b+2) // - 2/(b+2)

3/(2*b-1)-(2/(b+2)) = 0

3/(2*b-1)-2*(b+2)^-1 = 0

3/(2*b-1)-2/(b+2) = 0

(3*(b+2))/((2*b-1)*(b+2))+(-2*(2*b-1))/((2*b-1)*(b+2)) = 0

3*(b+2)-2*(2*b-1) = 0

8-b = 0

(8-b)/((2*b-1)*(b+2)) = 0

(8-b)/((2*b-1)*(b+2)) = 0 // * (2*b-1)*(b+2)

8-b = 0

8-b = 0 // - 8

-b = -8 // * -1

b = 8

b = 8

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