3/(2m+4)=(1/(m+2))-2

Solution for 3/(2m+4)=(1/(m+2))-2 equation:

3/(2m+4)=(1/(m+2))-2

We move all terms to the left:

3/(2m+4)-((1/(m+2))-2)=0


Domain of the equation: (2m+4)!=0

We move all terms containing m to the left, all other terms to the right

2m!=-4

m!=-4/2

m!=-2

m∈R



Domain of the equation: (m+2))-2)!=0

m∈R


We calculate fractions


3m/((2m+4)*(m+2))-2))+(-((1*(2m+4))/((2m+4)*(m+2))-2))=0

We add all the numbers together, and all the variables

3m/((2m+4)*(m+2))-2))+(-((1*(2m+4))/((2m+4)*(m+2))=0

We multiply all the terms by the denominator


3m-2))+(-((1*(2m+4))=0