3/(2m+4)=(1/(m+2))-2

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Solution for 3/(2m+4)=(1/(m+2))-2 equation:



3/(2m+4)=(1/(m+2))-2
We move all terms to the left:
3/(2m+4)-((1/(m+2))-2)=0
Domain of the equation: (2m+4)!=0
We move all terms containing m to the left, all other terms to the right
2m!=-4
m!=-4/2
m!=-2
m∈R
Domain of the equation: (m+2))-2)!=0
m∈R
We calculate fractions
3m/((2m+4)*(m+2))-2))+(-((1*(2m+4))/((2m+4)*(m+2))-2))=0
We add all the numbers together, and all the variables
3m/((2m+4)*(m+2))-2))+(-((1*(2m+4))/((2m+4)*(m+2))=0
We multiply all the terms by the denominator
3m-2))+(-((1*(2m+4))=0

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