3/(2x+1)=-2/(x-5)

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Solution for 3/(2x+1)=-2/(x-5) equation: 



3/(2x+1)=-2/(x-5)

We move all terms to the left:

3/(2x+1)-(-2/(x-5))=0



Domain of the equation: (2x+1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-1

x!=-1/2

x!=-1/2

x∈R





Domain of the equation: (x-5))!=0

x∈R



We calculate fractions


3x/((2x+1)*(x-5)))+(-(-2*(2x+1))/((2x+1)*(x-5)))=0



We calculate terms in parentheses: -(-2*(2x+1))/((2x+1)*(x-5))), so:

-2*(2x+1))/((2x+1)*(x-5))

We multiply all the terms by the denominator


-2*(2x+1))

We multiply parentheses

-4x-

We add all the numbers together, and all the variables

-4x

Back to the equation:

-(-4x)



We get rid of parentheses

3x/((2x+1)*(x-5)))+(+4x=0

We multiply all the terms by the denominator


3x+4x*((2x+1)*(x-5)))+(=0

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