3/(2x+1)=9/3x

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Solution for 3/(2x+1)=9/3x equation: 



3/(2x+1)=9/3x

We move all terms to the left:

3/(2x+1)-(9/3x)=0



Domain of the equation: (2x+1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-1

x!=-1/2

x!=-1/2

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3/(2x+1)-(+9/3x)=0

We get rid of parentheses

3/(2x+1)-9/3x=0

We calculate fractions


9x/(6x^2+3x)+(-18x-9)/(6x^2+3x)=0

We multiply all the terms by the denominator


9x+(-18x-9)=0

We get rid of parentheses

9x-18x-9=0

We add all the numbers together, and all the variables

-9x-9=0

We move all terms containing x to the left, all other terms to the right

-9x=9

x=9/-9

x=-1

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