3/(2x-1)+4=6x/(2x-1)

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Solution for 3/(2x-1)+4=6x/(2x-1) equation:


D( x )

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

x in (-oo:1/2) U (1/2:+oo)

3/(2*x-1)+4 = (6*x)/(2*x-1) // - (6*x)/(2*x-1)

3/(2*x-1)-((6*x)/(2*x-1))+4 = 0

3/(2*x-1)-6*x*(2*x-1)^-1+4 = 0

3/(2*x-1)+(-6*x)/(2*x-1)+4 = 0

3/(2*x-1)+(-6*x)/(2*x-1)+(4*(2*x-1))/(2*x-1) = 0

4*(2*x-1)-6*x+3 = 0

8*x-6*x-4+3 = 0

2*x-1 = 0

(2*x-1)/(2*x-1) = 0

(2*x-1)/(2*x-1) = 0 // * 2*x-1

2*x-1 = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

x in { 1/2}

x belongs to the empty set

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