3/(2x-4)=4/(x-2)

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Solution for 3/(2x-4)=4/(x-2) equation: 



3/(2x-4)=4/(x-2)

We move all terms to the left:

3/(2x-4)-(4/(x-2))=0



Domain of the equation: (2x-4)!=0

We move all terms containing x to the left, all other terms to the right

2x!=4

x!=4/2

x!=2

x∈R





Domain of the equation: (x-2))!=0

x∈R



We calculate fractions


3x/((2x-4)*(x-2)))+(-(4*(2x-4))/((2x-4)*(x-2)))=0



We calculate terms in parentheses: -(4*(2x-4))/((2x-4)*(x-2))), so:

4*(2x-4))/((2x-4)*(x-2))

We multiply all the terms by the denominator


4*(2x-4))

We multiply parentheses

8x+

We add all the numbers together, and all the variables

8x

Back to the equation:

-(8x)



We add all the numbers together, and all the variables

-8x+3x/((2x-4)*(x-2)))+(=0

We multiply all the terms by the denominator


-8x*((2x-4)*(x-2)))+(+3x=0

We add all the numbers together, and all the variables

3x-8x*((2x-4)*(x-2)))+(=0

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