3/(2x-5)=6/2x

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Solution for 3/(2x-5)=6/2x equation: 



3/(2x-5)=6/2x

We move all terms to the left:

3/(2x-5)-(6/2x)=0



Domain of the equation: (2x-5)!=0

We move all terms containing x to the left, all other terms to the right

2x!=5

x!=5/2

x!=2+1/2

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3/(2x-5)-(+6/2x)=0

We get rid of parentheses

3/(2x-5)-6/2x=0

We calculate fractions


6x/(4x^2-10x)+(-12x+30)/(4x^2-10x)=0

We multiply all the terms by the denominator


6x+(-12x+30)=0

We get rid of parentheses

6x-12x+30=0

We add all the numbers together, and all the variables

-6x+30=0

We move all terms containing x to the left, all other terms to the right

-6x=-30

x=-30/-6

x=+5

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