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3/(2x-5)=6/2x
We move all terms to the left:
3/(2x-5)-(6/2x)=0
Domain of the equation: (2x-5)!=0
We move all terms containing x to the left, all other terms to the right
2x!=5
x!=5/2
x!=2+1/2
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/(2x-5)-(+6/2x)=0
We get rid of parentheses
3/(2x-5)-6/2x=0
We calculate fractions
6x/(4x^2-10x)+(-12x+30)/(4x^2-10x)=0
We multiply all the terms by the denominator
6x+(-12x+30)=0
We get rid of parentheses
6x-12x+30=0
We add all the numbers together, and all the variables
-6x+30=0
We move all terms containing x to the left, all other terms to the right
-6x=-30
x=-30/-6
x=+5
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