3/(2y)=16/(y+2)

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Solution for 3/(2y)=16/(y+2) equation: 


D( y )

y+2 = 0

2*y = 0

y+2 = 0

y+2 = 0

y+2 = 0 // - 2

y = -2

2*y = 0

2*y = 0

2*y = 0 // : 2

y = 0

y in (-oo:-2) U (-2:0) U (0:+oo)

3/(2*y) = 16/(y+2) // - 16/(y+2)

3/(2*y)-(16/(y+2)) = 0

3/(2*y)-16*(y+2)^-1 = 0

3/(2*y)-16/(y+2) = 0

(-16*2*y)/(2*y*(y+2))+(3*(y+2))/(2*y*(y+2)) = 0

3*(y+2)-16*2*y = 0

6-29*y = 0

(6-29*y)/(2*y*(y+2)) = 0

(6-29*y)/(2*y*(y+2)) = 0 // * 2*y*(y+2)

6-29*y = 0

6-29*y = 0 // - 6

-29*y = -6 // : -29

y = -6/(-29)

y = 6/29

y = 6/29

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