3/(3b+7)=2/(b-7)

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Solution for 3/(3b+7)=2/(b-7) equation: 



3/(3b+7)=2/(b-7)

We move all terms to the left:

3/(3b+7)-(2/(b-7))=0



Domain of the equation: (3b+7)!=0

We move all terms containing b to the left, all other terms to the right

3b!=-7

b!=-7/3

b!=-2+1/3

b∈R





Domain of the equation: (b-7))!=0

b∈R



We calculate fractions


3b/((3b+7)*(b-7)))+(-(2*(3b+7))/((3b+7)*(b-7)))=0



We calculate terms in parentheses: -(2*(3b+7))/((3b+7)*(b-7))), so:

2*(3b+7))/((3b+7)*(b-7))

We multiply all the terms by the denominator


2*(3b+7))

We multiply parentheses

6b+

We add all the numbers together, and all the variables

6b

Back to the equation:

-(6b)



We add all the numbers together, and all the variables

-6b+3b/((3b+7)*(b-7)))+(=0

We multiply all the terms by the denominator


-6b*((3b+7)*(b-7)))+(+3b=0

We add all the numbers together, and all the variables

3b-6b*((3b+7)*(b-7)))+(=0

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