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3/(5)x+12=2x-3
We move all terms to the left:
3/(5)x+12-(2x-3)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
3/5x-2x+3+12=0
We multiply all the terms by the denominator
-2x*5x+3*5x+12*5x+3=0
Wy multiply elements
-10x^2+15x+60x+3=0
We add all the numbers together, and all the variables
-10x^2+75x+3=0
a = -10; b = 75; c = +3;
Δ = b2-4ac
Δ = 752-4·(-10)·3
Δ = 5745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-\sqrt{5745}}{2*-10}=\frac{-75-\sqrt{5745}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+\sqrt{5745}}{2*-10}=\frac{-75+\sqrt{5745}}{-20} $
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