3/(6x+4)=1/(9x+6)

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Solution for 3/(6x+4)=1/(9x+6) equation:


D( x )

9*x+6 = 0

6*x+4 = 0

9*x+6 = 0

9*x+6 = 0

9*x+6 = 0 // - 6

9*x = -6 // : 9

x = -6/9

x = -2/3

6*x+4 = 0

6*x+4 = 0

6*x+4 = 0 // - 4

6*x = -4 // : 6

x = -4/6

x = -2/3

x in (-oo:-2/3) U (-2/3:+oo)

3/(6*x+4) = 1/(9*x+6) // - 1/(9*x+6)

3/(6*x+4)-(1/(9*x+6)) = 0

3/(6*x+4)-(9*x+6)^-1 = 0

3/(6*x+4)-1/(9*x+6) = 0

(3*(9*x+6))/((6*x+4)*(9*x+6))+(-1*(6*x+4))/((6*x+4)*(9*x+6)) = 0

3*(9*x+6)-1*(6*x+4) = 0

21*x+14 = 0

(21*x+14)/((6*x+4)*(9*x+6)) = 0

(21*x+14)/((6*x+4)*(9*x+6)) = 0 // * (6*x+4)*(9*x+6)

21*x+14 = 0

21*x+14 = 0 // - 14

21*x = -14 // : 21

x = -14/21

x = -2/3

x in { -2/3}

x belongs to the empty set

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