3/(7x-1)+1/x=0

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Solution for 3/(7x-1)+1/x=0 equation: 



3/(7x-1)+1/x=0



Domain of the equation: (7x-1)!=0

We move all terms containing x to the left, all other terms to the right

7x!=1

x!=1/7

x!=1/7

x∈R





Domain of the equation: x!=0

x∈R



We calculate fractions


3x/(7x^2-1x)+(1*(7x-1))/(7x^2-1x)=0



We calculate terms in parentheses: +(1*(7x-1))/(7x^2-1x), so:

1*(7x-1))/(7x^2-1x

We add all the numbers together, and all the variables

-1x+1*(7x-1))/(7x^2

We multiply all the terms by the denominator


-1x*(7x^2+1*(7x-1))

Back to the equation:

+(-1x*(7x^2+1*(7x-1)))



We multiply all the terms by the denominator


3x+((-1x*(7x^2+1*(7x-1))))*(7x^2-1x)=0



We calculate terms in parentheses: +((-1x*(7x^2+1*(7x-1))))*(7x^2-1x), so:

(-1x*(7x^2+1*(7x-1))))*(7x^2-1x

We add all the numbers together, and all the variables

-1x+(-1x*(7x^2+1*(7x-1))))*(7x^2

Back to the equation:

+(-1x+(-1x*(7x^2+1*(7x-1))))*(7x^2)

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