3/(8x+1)+8/(2x+5)=1

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Solution for 3/(8x+1)+8/(2x+5)=1 equation: 



3/(8x+1)+8/(2x+5)=1

We move all terms to the left:

3/(8x+1)+8/(2x+5)-(1)=0



Domain of the equation: (8x+1)!=0

We move all terms containing x to the left, all other terms to the right

8x!=-1

x!=-1/8

x!=-1/8

x∈R





Domain of the equation: (2x+5)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-5

x!=-5/2

x!=-2+1/2

x∈R



We calculate fractions


(6x+15)/((8x+1)*(2x+5))+(64x+8)/((8x+1)*(2x+5))-1=0



We calculate terms in parentheses: +(6x+15)/((8x+1)*(2x+5)), so:

6x+15)/((8x+1)*(2x+5)

We multiply all the terms by the denominator


6x*((8x+1)*(2x+5)+15)

Back to the equation:

+(6x*((8x+1)*(2x+5)+15))





We calculate terms in parentheses: +(64x+8)/((8x+1)*(2x+5)), so:

64x+8)/((8x+1)*(2x+5)

We multiply all the terms by the denominator


64x*((8x+1)*(2x+5)+8)

Back to the equation:

+(64x*((8x+1)*(2x+5)+8))





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parentheses: +(64x*((8x+1)*(2x+5)+8)), so:

64x*((8x+1)*(2x+5)+8)





We calculate terms in parentheses: +(6x*((8x+1)*(2x+5)+15)), so:

6x*((8x+1)*(2x+5)+15)





We calculate terms in parenthe

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