3/(a-4)=a/(a-2)

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Solution for 3/(a-4)=a/(a-2) equation:


D( a )

a-4 = 0

a-2 = 0

a-4 = 0

a-4 = 0

a-4 = 0 // + 4

a = 4

a-2 = 0

a-2 = 0

a-2 = 0 // + 2

a = 2

a in (-oo:2) U (2:4) U (4:+oo)

3/(a-4) = a/(a-2) // - a/(a-2)

3/(a-4)-(a/(a-2)) = 0

3/(a-4)+(-1*a)/(a-2) = 0

(3*(a-2))/((a-4)*(a-2))+(-1*a*(a-4))/((a-4)*(a-2)) = 0

3*(a-2)-1*a*(a-4) = 0

7*a-a^2-6 = 0

7*a-a^2-6 = 0

7*a-a^2-6 = 0

DELTA = 7^2-(-6*(-1)*4)

DELTA = 25

DELTA > 0

a = (25^(1/2)-7)/(-1*2) or a = (-25^(1/2)-7)/(-1*2)

a = 1 or a = 6

(a-1)*(a-6) = 0

((a-1)*(a-6))/((a-4)*(a-2)) = 0

((a-1)*(a-6))/((a-4)*(a-2)) = 0 // * (a-4)*(a-2)

(a-1)*(a-6) = 0

( a-1 )

a-1 = 0 // + 1

a = 1

( a-6 )

a-6 = 0 // + 6

a = 6

a in { 1, 6 }

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