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3/(m-1)=6/3m+8
We move all terms to the left:
3/(m-1)-(6/3m+8)=0
Domain of the equation: (m-1)!=0
We move all terms containing m to the left, all other terms to the right
m!=1
m∈R
Domain of the equation: 3m+8)!=0We get rid of parentheses
m∈R
3/(m-1)-6/3m-8=0
We calculate fractions
9m/(3m^2-3m)+(-6m+6)/(3m^2-3m)-8=0
We multiply all the terms by the denominator
9m+(-6m+6)-8*(3m^2-3m)=0
We multiply parentheses
-24m^2+9m+(-6m+6)+24m=0
We get rid of parentheses
-24m^2+9m-6m+24m+6=0
We add all the numbers together, and all the variables
-24m^2+27m+6=0
a = -24; b = 27; c = +6;
Δ = b2-4ac
Δ = 272-4·(-24)·6
Δ = 1305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1305}=\sqrt{9*145}=\sqrt{9}*\sqrt{145}=3\sqrt{145}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-3\sqrt{145}}{2*-24}=\frac{-27-3\sqrt{145}}{-48} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+3\sqrt{145}}{2*-24}=\frac{-27+3\sqrt{145}}{-48} $
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