3/(n+1)=5/(n-1)

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Solution for 3/(n+1)=5/(n-1) equation: 


D( n )

n-1 = 0

n+1 = 0

n-1 = 0

n-1 = 0

n-1 = 0 // + 1

n = 1

n+1 = 0

n+1 = 0

n+1 = 0 // - 1

n = -1

n in (-oo:-1) U (-1:1) U (1:+oo)

3/(n+1) = 5/(n-1) // - 5/(n-1)

3/(n+1)-(5/(n-1)) = 0

3/(n+1)-5*(n-1)^-1 = 0

3/(n+1)-5/(n-1) = 0

(3*(n-1))/((n+1)*(n-1))+(-5*(n+1))/((n+1)*(n-1)) = 0

3*(n-1)-5*(n+1) = 0

-2*n-8 = 0

(-2*n-8)/((n+1)*(n-1)) = 0

(-2*n-8)/((n+1)*(n-1)) = 0 // * (n+1)*(n-1)

-2*n-8 = 0

-2*n-8 = 0 // + 8

-2*n = 8 // : -2

n = 8/(-2)

n = -4

n = -4

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