3/(n-1)=5/(n-3)

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Solution for 3/(n-1)=5/(n-3) equation: 


D( n )

n-1 = 0

n-3 = 0

n-1 = 0

n-1 = 0

n-1 = 0 // + 1

n = 1

n-3 = 0

n-3 = 0

n-3 = 0 // + 3

n = 3

n in (-oo:1) U (1:3) U (3:+oo)

3/(n-1) = 5/(n-3) // - 5/(n-3)

3/(n-1)-(5/(n-3)) = 0

3/(n-1)-5*(n-3)^-1 = 0

3/(n-1)-5/(n-3) = 0

(3*(n-3))/((n-1)*(n-3))+(-5*(n-1))/((n-1)*(n-3)) = 0

3*(n-3)-5*(n-1) = 0

-2*n-4 = 0

(-2*n-4)/((n-1)*(n-3)) = 0

(-2*n-4)/((n-1)*(n-3)) = 0 // * (n-1)*(n-3)

-2*n-4 = 0

-2*n-4 = 0 // + 4

-2*n = 4 // : -2

n = 4/(-2)

n = -2

n = -2

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