3/(p-6)=1/p

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Solution for 3/(p-6)=1/p equation: 



3/(p-6)=1/p

We move all terms to the left:

3/(p-6)-(1/p)=0



Domain of the equation: (p-6)!=0

We move all terms containing p to the left, all other terms to the right

p!=6

p∈R





Domain of the equation: p)!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

3/(p-6)-(+1/p)=0

We get rid of parentheses

3/(p-6)-1/p=0

We calculate fractions


3p/(p^2-6p)+(-1*(p-6))/(p^2-6p)=0



We calculate terms in parentheses: +(-1*(p-6))/(p^2-6p), so:

-1*(p-6))/(p^2-6p

We add all the numbers together, and all the variables

-6p-1*(p-6))/(p^2

We multiply all the terms by the denominator


-6p*(p^2-1*(p-6))

Back to the equation:

+(-6p*(p^2-1*(p-6)))



We multiply all the terms by the denominator


3p+((-6p*(p^2-1*(p-6))))*(p^2-6p)=0



We calculate terms in parentheses: +((-6p*(p^2-1*(p-6))))*(p^2-6p), so:

(-6p*(p^2-1*(p-6))))*(p^2-6p

We add all the numbers together, and all the variables

-6p+(-6p*(p^2-1*(p-6))))*(p^2

Back to the equation:

+(-6p+(-6p*(p^2-1*(p-6))))*(p^2)

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