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3/(x+1)-1/2=1/(3x+3)
We move all terms to the left:
3/(x+1)-1/2-(1/(3x+3))=0
Domain of the equation: (x+1)!=0
We move all terms containing x to the left, all other terms to the right
x!=-1
x∈R
Domain of the equation: (3x+3))!=0We calculate fractions
x∈R
18x/((x+1)*(3x+3))*2)+(-(1*(x+1)*2)/((x+1)*(3x+3))*2)+(-1*(x+1)*(3x+3)))/((x+1)*(3x+3))*2)=0
We add all the numbers together, and all the variables
18x/((x+1)*(3x+3))*2)+(-(1*(x+1)*2)/((x+1)*(3x+3))*2)+(-1*(x+1)*(3x+3)))/((x+1)*(3x=0
We calculate fractions
1)*(3x+(18x-(1*(x+1)*2)*(x/(((x+1)*(3x+3))*2)+(*(x+(-1*(x+1)*(3x+3)))*((x+1)*3x/(((x+1)*(3x+3))*2)+(*(x=0
We can not solve this equation
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