3/(x+1)=2/(x-4)

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Solution for 3/(x+1)=2/(x-4) equation: 


D( x )

x+1 = 0

x-4 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:-1) U (-1:4) U (4:+oo)

3/(x+1) = 2/(x-4) // - 2/(x-4)

3/(x+1)-(2/(x-4)) = 0

3/(x+1)-2*(x-4)^-1 = 0

3/(x+1)-2/(x-4) = 0

(3*(x-4))/((x+1)*(x-4))+(-2*(x+1))/((x+1)*(x-4)) = 0

3*(x-4)-2*(x+1) = 0

x-14 = 0

(x-14)/((x+1)*(x-4)) = 0

(x-14)/((x+1)*(x-4)) = 0 // * (x+1)*(x-4)

x-14 = 0

x-14 = 0 // + 14

x = 14

x = 14

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