3/(x+2)=4/(6+x)

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Solution for 3/(x+2)=4/(6+x) equation: 



3/(x+2)=4/(6+x)

We move all terms to the left:

3/(x+2)-(4/(6+x))=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (6+x))!=0

We move all terms containing x to the left, all other terms to the right

x)!=-6

x!=-6/1

x!=-6

x∈R



We add all the numbers together, and all the variables

3/(x+2)-(4/(x+6))=0

We calculate fractions


3x/((x+2)*(x+6)))+(-(4*(x+2))/((x+2)*(x+6)))=0



We calculate terms in parentheses: -(4*(x+2))/((x+2)*(x+6))), so:

4*(x+2))/((x+2)*(x+6))

We multiply all the terms by the denominator


4*(x+2))

We multiply parentheses

4x+

We add all the numbers together, and all the variables

4x

Back to the equation:

-(4x)



We add all the numbers together, and all the variables

-4x+3x/((x+2)*(x+6)))+(=0

We multiply all the terms by the denominator


-4x*((x+2)*(x+6)))+(+3x=0

We add all the numbers together, and all the variables

3x-4x*((x+2)*(x+6)))+(=0

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