3/(x+4)=1/x

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Solution for 3/(x+4)=1/x equation: 



3/(x+4)=1/x

We move all terms to the left:

3/(x+4)-(1/x)=0



Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3/(x+4)-(+1/x)=0

We get rid of parentheses

3/(x+4)-1/x=0

We calculate fractions


3x/(x^2+4x)+(-1*(x+4))/(x^2+4x)=0



We calculate terms in parentheses: +(-1*(x+4))/(x^2+4x), so:

-1*(x+4))/(x^2+4x

We add all the numbers together, and all the variables

4x-1*(x+4))/(x^2

We multiply all the terms by the denominator


4x*(x^2-1*(x+4))

Back to the equation:

+(4x*(x^2-1*(x+4)))



We multiply all the terms by the denominator


3x+((4x*(x^2-1*(x+4))))*(x^2+4x)=0



We calculate terms in parentheses: +((4x*(x^2-1*(x+4))))*(x^2+4x), so:

(4x*(x^2-1*(x+4))))*(x^2+4x

We add all the numbers together, and all the variables

4x+(4x*(x^2-1*(x+4))))*(x^2

Back to the equation:

+(4x+(4x*(x^2-1*(x+4))))*(x^2)

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