3/(x-2)=4/(3x+4)

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Solution for 3/(x-2)=4/(3x+4) equation: 



3/(x-2)=4/(3x+4)

We move all terms to the left:

3/(x-2)-(4/(3x+4))=0



Domain of the equation: (x-2)!=0

We move all terms containing x to the left, all other terms to the right

x!=2

x∈R





Domain of the equation: (3x+4))!=0

x∈R



We calculate fractions


9x/((x-2)*(3x+4)))+(-(4*(x-2))/((x-2)*(3x+4)))=0



We calculate terms in parentheses: -(4*(x-2))/((x-2)*(3x+4))), so:

4*(x-2))/((x-2)*(3x+4))

We multiply all the terms by the denominator


4*(x-2))

We multiply parentheses

4x+

We add all the numbers together, and all the variables

4x

Back to the equation:

-(4x)



We add all the numbers together, and all the variables

-4x+9x/((x-2)*(3x+4)))+(=0

We multiply all the terms by the denominator


-4x*((x-2)*(3x+4)))+(+9x=0

We add all the numbers together, and all the variables

9x-4x*((x-2)*(3x+4)))+(=0

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