3/(y+5)-6/(y-5)=12/(y2-25)

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Solution for 3/(y+5)-6/(y-5)=12/(y2-25) equation:


D( y )

y^2-25 = 0

y-5 = 0

y+5 = 0

y^2-25 = 0

y^2-25 = 0

1*y^2 = 25 // : 1

y^2 = 25

y^2 = 25 // ^ 1/2

abs(y) = 5

y = 5 or y = -5

y-5 = 0

y-5 = 0

y-5 = 0 // + 5

y = 5

y+5 = 0

y+5 = 0

y+5 = 0 // - 5

y = -5

y in (-oo:-5) U (-5:5) U (5:+oo)

3/(y+5)-(6/(y-5)) = 12/(y^2-25) // - 12/(y^2-25)

3/(y+5)-(6/(y-5))-(12/(y^2-25)) = 0

3/(y+5)-6*(y-5)^-1-12*(y^2-25)^-1 = 0

3/(y+5)-6/(y-5)-12/(y^2-25) = 0

(3*(y-5)*(y^2-25))/((y+5)*(y-5)*(y^2-25))+(-6*(y+5)*(y^2-25))/((y+5)*(y-5)*(y^2-25))+(-12*(y+5)*(y-5))/((y+5)*(y-5)*(y^2-25)) = 0

3*(y-5)*(y^2-25)-6*(y+5)*(y^2-25)-12*(y+5)*(y-5) = 0

75*y-3*y^3-45*y^2-12*y^2+300+1125 = 0

75*y-3*y^3-57*y^2+1425 = 0

75*y-3*y^3-57*y^2+1425 = 0

3*(25*y-y^3-19*y^2+475) = 0

25*y-y^3-19*y^2+475

y*(25-y^2)-19*y^2+475

19*(25-y^2)+y*(25-y^2)

(y+19)*(25-y^2)

3*(y+19)*(25-y^2) = 0

(3*(y+19)*(25-y^2))/((y+5)*(y-5)*(y^2-25)) = 0

(3*(y+19)*(25-y^2))/((y+5)*(y-5)*(y^2-25)) = 0 // * (y+5)*(y-5)*(y^2-25)

3*(y+19)*(25-y^2) = 0

( 25-y^2 )

-1*y^2 = -25 // : -1

y^2 = 25

y^2 = 25 // ^ 1/2

abs(y) = 5

y = 5 or y = -5

( y+19 )

y+19 = 0 // - 19

y = -19

y in { 5}

y in { -5}

y = -19

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