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3/1+2x=5/3x-2
We move all terms to the left:
3/1+2x-(5/3x-2)=0
Domain of the equation: 3x-2)!=0We add all the numbers together, and all the variables
x∈R
2x-(5/3x-2)=0
We get rid of parentheses
2x-5/3x+2=0
We multiply all the terms by the denominator
2x*3x+2*3x-5=0
Wy multiply elements
6x^2+6x-5=0
a = 6; b = 6; c = -5;
Δ = b2-4ac
Δ = 62-4·6·(-5)
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{39}}{2*6}=\frac{-6-2\sqrt{39}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{39}}{2*6}=\frac{-6+2\sqrt{39}}{12} $
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