3/10(12n-16)=2/5(12-3n)

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Solution for 3/10(12n-16)=2/5(12-3n) equation: 



3/10(12n-16)=2/5(12-3n)

We move all terms to the left:

3/10(12n-16)-(2/5(12-3n))=0



Domain of the equation: 10(12n-16)!=0

n∈R





Domain of the equation: 5(12-3n))!=0

n∈R



We add all the numbers together, and all the variables

3/10(12n-16)-(2/5(-3n+12))=0

We calculate fractions


(15n(-)/(10(12n-16)*5(-3n+12)))+(-20n1/(10(12n-16)*5(-3n+12)))=0



We calculate terms in parentheses: +(15n(-)/(10(12n-16)*5(-3n+12))), so:

15n(-)/(10(12n-16)*5(-3n+12))

We add all the numbers together, and all the variables

15n0/(10(12n-16)*5(-3n+12))

We multiply all the terms by the denominator


15n0

We add all the numbers together, and all the variables

15n

Back to the equation:

+(15n)





We calculate terms in parentheses: +(-20n1/(10(12n-16)*5(-3n+12))), so:

-20n1/(10(12n-16)*5(-3n+12))

We multiply all the terms by the denominator


-20n1

We add all the numbers together, and all the variables

-20n

Back to the equation:

+(-20n)



We get rid of parentheses

15n-20n=0

We add all the numbers together, and all the variables

-5n=0

n=0/-5

n=0

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