3/10(12x-16)=2/5(12-3x)

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Solution for 3/10(12x-16)=2/5(12-3x) equation: 



3/10(12x-16)=2/5(12-3x)

We move all terms to the left:

3/10(12x-16)-(2/5(12-3x))=0



Domain of the equation: 10(12x-16)!=0

x∈R





Domain of the equation: 5(12-3x))!=0

x∈R



We add all the numbers together, and all the variables

3/10(12x-16)-(2/5(-3x+12))=0

We calculate fractions


(15x(-)/(10(12x-16)*5(-3x+12)))+(-20x1/(10(12x-16)*5(-3x+12)))=0



We calculate terms in parentheses: +(15x(-)/(10(12x-16)*5(-3x+12))), so:

15x(-)/(10(12x-16)*5(-3x+12))

We add all the numbers together, and all the variables

15x0/(10(12x-16)*5(-3x+12))

We multiply all the terms by the denominator


15x0

We add all the numbers together, and all the variables

15x

Back to the equation:

+(15x)





We calculate terms in parentheses: +(-20x1/(10(12x-16)*5(-3x+12))), so:

-20x1/(10(12x-16)*5(-3x+12))

We multiply all the terms by the denominator


-20x1

We add all the numbers together, and all the variables

-20x

Back to the equation:

+(-20x)



We get rid of parentheses

15x-20x=0

We add all the numbers together, and all the variables

-5x=0

x=0/-5

x=0

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